F(x)=5x^2-6-4x

Solution for F(x)=5x^2-6-4x equation:

(F)=5F^2-6-4F

We move all terms to the left:

(F)-(5F^2-6-4F)=0

We get rid of parentheses

-5F^2+F+4F+6=0

We add all the numbers together, and all the variables

-5F^2+5F+6=0

a = -5; b = 5; c = +6;
Δ = b2-4ac
Δ = 52-4·(-5)·6
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{145}}{2*-5}=\frac{-5-\sqrt{145}}{-10}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{145}}{2*-5}=\frac{-5+\sqrt{145}}{-10}
$